Theorem: Bethe Fermi-gas nuclear temperature T = sqrt(E)/sqrt(a) (thermodynamic 1/T = dS/dE)

Layer 1 — Physicsin the nuclear-reactions subtree

Theorem (Bethe nuclear-temperature canonical): the Hardy-Ramanujan / Fermi-gas leading entropy S(E) = 2 sqrt(a E) defines the microcanonical temperature T(E) via 1/T = dS/dE = sqrt(a/E), yielding T = sqrt(E)/sqrt(a) exactly. Canonical…

Related concepts

Explore Theorem: Bethe Fermi-gas nuclear temperature T = sqrt(E)/sqrt(a) (thermodynamic 1/T = dS/dE) on the interactive knowledge graph →