Rutherford cross-section: σ(π) = Z²Z²e⁴/(16E²); σ(π/2) = Z²Z²e⁴/(4E²); ratio σ(π/2)/σ(π) = 4

Layer 2 — Chemistryin the radiation-chemistry subtree

Angular-ratio fingerprint: σ(π/2)/σ(π) = sin⁴(π/2)/sin⁴(π/4) = 1/(1/4) = 4. Canonical pins: cross-section at θ=π (backscatter, σ=Z_p²Z_t²e_q⁴/(16E²)); at θ=π/2 (σ=Z_p²Z_t²e_q⁴/(4E²)); their ratio = 4 (exact integer).

Related concepts

Explore Rutherford cross-section: σ(π) = Z²Z²e⁴/(16E²); σ(π/2) = Z²Z²e⁴/(4E²); ratio σ(π/2)/σ(π) = 4 on the interactive knowledge graph →